Dnk - you know that in a household 120/240V service, the neutral carries only the unbalanced portion of the line current, the difference between L1 current and L2 current. In your example here, ignoring that fact that ØB even exists for the moment, the same thing is true. On ØC, 34KVA of the 41KVA load is balanced by the 34KVA on ØA, and the resulting current flows between ØC and ØA, not involving the neutral.
The unbalanced part of the load, 7KVA, is seen between ØC and the neutral. 7,000VA divided by 120V is approx equal to 58 amps. That is to say, the unbalanced part is 58 amps and flows between ØC and neutral.
The SINGLE PHASE component of the loads are sumarized thus (Kirchoff's Current Law):
ØA = 284 amps
Neutral = 58 amps
ØC = 342 amps (284 + 58)
I'm not sure I'm any good at describing this stuff, hope this helps.
Radar
