a 15H coil (inductor) carries a current of 7A. What amount of energy is stored in the magnetic field?
Need to know the Frequency applied to this Inductor, to figure Xl.
" = Greek lower case "pi", or 3.141592653589...)
Formula is: XL = 2pi FL
If F= 60Hz, then XL =:2 * 3.141592653589 * 60 * 15.0 = 5,654 Ohms
Find Voltage: E=IR
I = 7.0 Amps,
R = 5,654 Ohms
7.0 * 5,654 = 39,578 Volts.
Find Reactive Power: VAR= E * I
E = 39,578 Volts,
I = 7.0 Amps
VARs = 277,046 VARs.
--- Personal Note:
I think the value of the Inductor is quite large - 15H.
Substituting 0.0015H (15mH) for the Inductor results in a much more reasonable Reactive Component: 277.046 VARs, with a Potential Difference of 39.578 Volts (rounded to 40 Volts).
-- Scott (EE)
---let's see if these spec. characters work now!---