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#129938 12/12/05 11:24 PM
Joined: Dec 2005
Posts: 25
J
Member
Hello everyboby!

Core losses (mostly hysteresis and eddy currents [Foucault currents]) are not going to change (theoretically and with the usual simplifications) with the load increase. But load losses (I2R) will.

About the 6.5 KW you mention, Scott35 wrote an excellent answer (and previously Bjarney have said something about it) explaining that those are not KW. Some part or it, the lesser one, are KVA, and the other, the bigger one are KVAR (I’ll bet my shoes that the ratio is about 1 to 5).

So, when load is starting to be added to the transformer, the transformer imput impedance will start gain resistance and loose reactance. This means that the Q factor of the transformer equivalent circuit will start to decrease and the “stored energy” over “dissipated energy” ratio will go down.

For a 75 KVA transformer, the total losses at a load level of 40 % should be around 0.8 KW. If the transformer you mention is in good working condition I think you should try to measure this value (let’s make science!).

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#129939 12/16/05 02:01 PM
Joined: Dec 2004
Posts: 1,064
D
Member
Joe, go ahead. I'm listening.....


Dnk....

#129940 12/16/05 09:46 PM
Joined: Dec 2005
Posts: 25
J
Member
That's it! My brain is empty.

Oh.., if you want you can load the transformer up to 40% and measure (with your Fluke 2060) real power on both sides (input and output) and calculate the total loss (substracting). You can also use that instrument to measure the KVA in open circuit (the 6500 you were referring) to see the real magnitude of the core losses (no-load losses).

But if you are like me, without a penny in your pocket for a Fluke 2060 or similar, you can always use a normal True-RMS clamp meter and make the measures of voltages and currents to calculate KVAs, KWs and KVARs with pencil and eraser. If need some help with that just let me know.

Regards,

Joe.-

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