If the plant has a 0.60pf and the load is 4500 kva then the kvar = 3600.
As WFO says you can't substract KVA - KW.
KW = pf x kva = .6 x kva = 2700 kw.
KVAR = sqrt(KVA² - KW²) = 3600 kvar. The KW is the same regardless of the PF. If you improve the PF to 0.90 then the
KVA = KW/pf = 2700 kw/0.90 = 3000 kva.
KVAR = sqrt(KVA² - KW²)= sqrt(3000²-2700²)
KVAR = 1306 kvar.
The sync motor must be adding 3600 kvar -
1306 kvar = 2294 kvar.
(800 hp x 746 w/hp)/0.8 = 746 kw
KVA = sqrt(KW² + KVAR²) sqrt(746² + 2294²)
= 2412 KVA
PF KW/KVA = 746/2412 = 0.31 leading
This sounds strange.
jfwayer
What you say?
[This message has been edited by Bob (edited 10-11-2005).]
[This message has been edited by Bob (edited 10-11-2005).]
