When I added things up, it appeared that the compiled values were Apparent Power across a 3 Phase 3 Wire Circuit - as the total sum is 7190 VA.
Seeing that ØA and ØB draw 2568 Watts, and ØC draws 2054 Watts makes the Load look Reactive.
Could be the True Power (1.0 PF) is 2500 Watts across Lines A & B, but this would mean the Line C load would be L-N.
If the Balanced Load is 1666.667 Watts per Line, then that portion would be 1.0 PF (all True Power), and the remainder would be something else.
Using the values given by the O.P., here are some figures:
*A Total Apparent Power for the Load: 7,190 VA (Volt-Amps)
*B Power Factor = 0.695 (69.5%)
*C Total VARs (Volt-Amps Reactive) for this Load: 5,160 VARs
This is figuring the Total True Power (Watts) at 5,000 Watts.
Scott
