Here is a simple example of the Power Triangle, which will assist with the Power Factor conclusion:
(it also doubles as the Basic Impedance Triangle, and the Basic Pythagoris Theorym)
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4 Watts (True Power),
3 VARs (Reactive Power),
5 VAs (Apparent Power).
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Power Factor = 0.8 (80%) lagging
4 Watts is 80% of 5 VA.
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Some detail to these items:
*** WATTS ***
Watts = True Power,
KW = Kilo Watts = 1,000 Watts;
*** VA ***
VA = Volt-Amps = Apparent Power = Reactive Power and True Power compiled,
KVA = Kilo Volt-Amps = 1,000 Volt-Amps = 1,000 VA;
*** VAR ***
VAR = Volt-Amps Reactive = Reactive Power = Scuttle Power,
KVAR = Kilo Volt-Amps Reactive = 1,000 Volt-Amps Reactive = 1,000 VAR.
In the example values listed above, the preceeding relate to listed Trigonomic Terms:
<OL TYPE=A>
[*] 4 Watts = "Sine" (Base of the Triangle),
[*] 3 VARs = "Cosine" (Opposite side of Triangle),
[*] 5 VAs = "Tangent" (Hypotenuse)
</OL>
You can use this formula to find any single unknown value, as long as you have two known values.
Scott35
