ECN Electrical Forum - Discussion Forums for Electricians, Inspectors and Related Professionals
ECN Shout Chat
Top Posters(30 Days)
Recent Posts
VFD MotorFeeders
by gfretwell. 10/19/17 01:02 AM
Generator Cable Sizing
by brsele. 10/18/17 07:39 PM
What do you do?
by gfretwell. 10/17/17 01:08 AM
Good ol' copper pipe in the fuse holder trick
by HotLine1. 10/16/17 07:16 PM
Another generator question
by HotLine1. 10/16/17 07:02 PM
New in the Gallery:
Gallery Test
Popular Topics(Views)
241,415 Are you busy
177,387 Re: Forum
168,982 Need opinion
Who's Online Now
0 registered members (), 27 guests, and 7 spiders.
Key: Admin, Global Mod, Mod
Previous Thread
Next Thread
Print Thread
Rate This Thread
#38419 - 05/22/04 05:12 PM very basic electronics!!!!!!  
james S  Offline
Member
Joined: May 2003
Posts: 107
West England
when using resistors to limit the current for say an L E D have you not got to take into account the voltage drop the resistor will create if the led is dependent on a particular value of voltage?

i know silly questions time!!!

can't see wood for the trees maybe?


Work Gear for Electricians and the Trades

#38420 - 05/22/04 05:31 PM Re: very basic electronics!!!!!!  
NJwirenut  Offline
Member
Joined: Sep 2001
Posts: 806
Bergen County, NJ
You need to know the forward voltage drop of the LED, and the current rating. A typical red LED will have a forward voltage drop of ~1.4 VDC, which is essentially independent of current. Other colors have slightly higher voltage drops, with blue being the highest at ~3 VDC

Basically, you subtract the LED voltage drop from the supply voltage, and then use ohm's law to select a resistor that will drop the remainder of the voltage at the desired current. An example:

Powering a green LED with a voltage drop of 1.6 V and a current rating of 15 mA. Supply voltage 24 VDC.

24VDC (supply voltage) - 1.6 V (LED drop) = 22.4 V (drop across resistor)

Resistance = 22.4V / 0.015A = 1493 ohms

Closest standard value would 1.5K ohms.

Power dissipated in the resistor would be:

22.4V * 0.015A = .336 Watts

Next higher standard value would be 1/2 W




[This message has been edited by NJwirenut (edited 05-22-2004).]


#38421 - 05/22/04 09:08 PM Re: very basic electronics!!!!!!  
hbiss  Offline
Member
Joined: Dec 2003
Posts: 886
Hawthorne, NY USA
No, not really because the LED draws so little current. I normally just ignore that the LED is in the circuit and select the series resistor to limit the current to the required value when placed across the supply voltage.

-Hal


#38422 - 05/22/04 11:11 PM Re: very basic electronics!!!!!!  
Bjarney  Offline
Moderator
Joined: Apr 2002
Posts: 2,527
West-Southern Inner-Northeast ...
See also www.ledmuseum.org/ledlinks.htm for several “resistor calculators” and a lot of LED-application data.

www.ledmuseum.org is itself an admirable and enormous collection of practical LED information and history, and well known for many merciless LED-flashlight reviews in “The Punishment Zone.”




[This message has been edited by Bjarney (edited 05-22-2004).]


#38423 - 05/22/04 11:50 PM Re: very basic electronics!!!!!!  
wa2ise  Offline
Member
Joined: Nov 2002
Posts: 784
Oradell NJ USA
Quote
I normally just ignore that the LED is in the circuit and select the series resistor to limit the current to the required value when placed across the supply voltage.


Ignoring the LED voltage drop doesn't much matter when the supply voltage is much higher than the LED drop. But if the supply voltage is 2V you definately need to consider the LED voltage drop. For a red LED (1.4V) you'd need a 40 ohm resistor to pass 15ma thru the LED. Ignore the LED drop and select a resistor based on 2V/15ma = 133 ohms, and use it with the red LED and you'll only get 4.5ma thru the LED. The LED will be much dimmer than desired.


#38424 - 05/23/04 01:43 AM Re: very basic electronics!!!!!!  
hbiss  Offline
Member
Joined: Dec 2003
Posts: 886
Hawthorne, NY USA
Agreed.


#38425 - 05/23/04 05:24 AM Re: very basic electronics!!!!!!  
pauluk  Offline
Member
Joined: Aug 2001
Posts: 7,520
Norfolk, England
I think everyone else has beaten me to all the calculations, but one other area where you might want to adjust the resistor values (and thus the LED's forward current) more accurately is where you're using a dual red/green LED.

By careful adjustment of the red and green currents you can obtain varying shades of yellow and orange for some applications.


#38426 - 05/26/04 12:49 AM Re: very basic electronics!!!!!!  
480 kicks like a mule  Offline
Member
Joined: May 2004
Posts: 13
leesburg, ga - usa
not to confuse anyone...make sure that your not dealing with an OLED also...it is organic in nature but has a different set of rules...

when in doubt...put 480 on it !!!

that was a joke...don't play with 480 and led's...they can curl your toes !


...Despite all my RAGE, I am STILL just a rat in a cage...

#38427 - 06/17/04 01:47 AM Re: very basic electronics!!!!!!  
PEdoubleNIZZLE  Offline
Member
Joined: Jun 2004
Posts: 176
McKeesport, PA, USA
I usually use this method:
(derived from R=E/I)
R=(V-Vf)/I
R=Resistor Needed
V=Voltage applied to the resistor and LED
Vf is the forward voltage of the LED.
I is the current used by the LED (typically 20mA for red.) Remember, I is in Amps, so you must convert the LED's req'd mA into A.
An LED is a current device, not a voltage device. It will always drop the voltage by Vf. Adding more current will make them brighter.



Member Spotlight
JoeKP
JoeKP
Berkley, MA
Posts: 144
Joined: March 2008
Show All Member Profiles 
Featured:

2017 Master Electrician Exam Preparation Combos
2017 NEC Electrician
Exam Prep Combos:
Master / Journeyman

 

Shout Box
Powered by UBB.threads™ PHP Forum Software 7.6.0
Page Time: 0.019s Queries: 14 (0.004s) Memory: 0.8018 MB (Peak: 0.9689 MB) Zlib enabled. Server Time: 2017-10-20 21:42:14 UTC