ECN Electrical Forum - Discussion Forums for Electricians, Inspectors and Related Professionals
ECN Shout Chat
Top Posters(30 Days)
Potseal 11
Recent Posts
1913 American Electrician's Handbook
by annemarie1. 07/27/17 03:10 PM
600 KW 120/208 3 Phase Y protection
by Yooperup. 07/24/17 12:20 PM
Green House wiring
by ghost307. 07/20/17 09:10 AM
Permit Snafus...AHJs and Contractors Jump in
by HotLine1. 07/18/17 08:06 PM
New in the Gallery:
Housebilding DIY wiring
Popular Topics(Views)
239,371 Are you busy
174,827 Re: Forum
167,217 Need opinion
Who's Online Now
0 registered members (), 59 guests, and 3 spiders.
Key: Admin, Global Mod, Mod
Previous Thread
Next Thread
Print Thread
Rate This Thread
#129609 - 05/23/05 11:29 PM Magnetic forces on non-braced cables  
mustangwilly  Offline
Junior Member
Joined: May 2005
Posts: 1
Roanoke, VA, USA
How can I calculate the forces on non-braced cables during a fault? The cables are freestanding and rub against several undesireable places. I am concerned the insulation will be compromised, the screening exposed and thus generate additional spectaculor results. It is a 5KV cable.


Tools for Electricians:

#129610 - 05/26/05 07:17 AM Re: Magnetic forces on non-braced cables  
winnie  Offline
Member
Joined: Sep 2003
Posts: 649
boston, ma
I don't know the equations that apply for determining the force over time in faulted three phase circuits.

The DC equation is pretty simple, this equation also applies for the 'instantaneous' force between two conductors at a given moment in time if the current is changing (note): the force between two current carrying conductors is proportional to the current in one times the current in the other, and inversely proportional to the distance between them. (note: this is only strictly true for changing currents if you ignore the speed of light [Linked Image] )

See http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/wirfor.html for the equation and a calculator.

After you've calculated the force between the conductors, you will also need to consider the geometry of the situation. Even if the conductor forces are not all that high per unit length, it may be that the force on a length of cable creates a concentrated load at a single point on the cable where it hits a support.

-Jon



Member Spotlight
Scott35
Scott35
Anaheim, CA. USA
Posts: 2,707
Joined: October 2000
Show All Member Profiles 
Featured:

2017 Master Electrician Exam Preparation Combos
2017 NEC Electrician
Exam Prep Combos:
Master / Journeyman

 

Shout Box
Powered by UBB.threads™ PHP Forum Software 7.6.0
Page Time: 0.009s Queries: 14 (0.003s) Memory: 0.7441 MB (Peak: 0.8628 MB) Zlib enabled. Server Time: 2017-07-28 13:01:31 UTC