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Load Calc for 18kV W/H
#91527
01/20/05 11:24 PM

Joined: Jan 2005
Posts: 20
OP
Member

How would the load calc break down for an 18kV Water Heater when:
Commercial Installation Service 208y/120 3P 4W
FLA = 57A (from manufacturers spec sheet)
This w/h has 4 heating elements  4500w each
Thanks, Mario
[This message has been edited by LoadnCode (edited 01202005).]
[This message has been edited by LoadnCode (edited 01202005).]



Re: Load Calc for 18kV W/H
#91528
01/21/05 12:45 AM

Joined: Jan 2005
Posts: 20
OP
Member

Do I calculate as follows:
A) (This would be true for Single Phase) 57A * 208V = 11856VA
even though i think this is the formula for 3p B) x in VA/(208V*1.732)= y in amps PER phase
If B) is correct then it would seem that C) would be correct...
C) 57A * 208V * 1.732 = 20,534.59VA PER phase



Re: Load Calc for 18kV W/H
#91529
01/21/05 09:00 AM

Joined: Jan 2004
Posts: 1,507
Member

I follow your math but I'm somewhat confused by the fact that the manufacturer tells you the ampere rating and the kw rating. The kw rating is all you need to size the service or the circuit. The ampere rating is going to vary depending on the voltage. So size the circuit using the kw rating and Article 422 and size the Service based on the kw rating of the water heater.
George Little



Re: Load Calc for 18kV W/H
#91530
01/21/05 09:22 AM

Joined: Sep 2003
Posts: 650
Member

You've swapped your root 3.
3 phase VA = amps * volts * 1.732
3 phase amps = VA / volts / 1.732
The reason is that when a three phase circuit is described as carrying X amps, this means X amps per leg, and when the voltage of a three phase circuit is described, this is the line to line voltage. If you convert things to 'line to neutral' voltage, and consider 'aggregate amps' (the total current down all of the wires) then the above equations make more sense, because now VA is simply volts times amps.
In a three phase 'wye' circuit, the line to neutral voltage is the line to line voltage/1.732
P.S. I think that the manufacturer needs to supply the amp rating because with _4_ heating elements, this is probably an unbalanced load.
Jon



Re: Load Calc for 18kV W/H
#91531
01/21/05 10:09 AM

Joined: Jan 2005
Posts: 20
OP
Member

Thanks George & Jon,
How is this calculated for the unbalanced load?
Thanks, Mario



Re: Load Calc for 18kV W/H
#91532
01/21/05 05:31 PM

Joined: Jan 2005
Posts: 9
Junior Member

all you need is the KW rating or FLA, if it is a storage type water heater, 120 gallons or less, 422.13 says the branch circuit supplying the water must have a rating of not less than 125% of the nameplate rating.



Re: Load Calc for 18kV W/H
#91533
01/21/05 06:18 PM

Joined: Jan 2005
Posts: 354
Member

BEWARE that a W/H with 4 elements will NOT be balanced across three phases. Each element is actually a single phase load. Assuming they are 208 volt elements, each 4500 watt element will pull 21.65 amps. But those amps will not be distributed evenly across the phases.
Assuming 1 element is connected AB, and 1 element is connected BC, and 2 elements are connected CA, you will have phase B carrying the sum of 21.65 amps at 0 degrees and 21.65 amps at 120 degrees. That adds up to 37.5 amps. But phases A and C have 21.65 amps at 0 degrees and 43.3 amps at 120 degrees. Adding that up gives 57.28 amps. So the manufacturer rating of 57A is about right (but a tad low). It's just phases A and C that will carry the 57.28 amps while phase B carries only 37.5 amps.
If the W/H had 3 elements of 6000w, then each would draw 28.82 amps (at 208 volts) and when balanced across three phases that would add up to a nice round 50.0 amps. But since there are 4 elements, it's not balanced, and the load is lopsided.
If you happen to have multiple water heaters of this type, then you'd want to rotate some of the phases to better distribute the total load. But for just one, you'll need to use the full 57.28 amps. And 125% of that is 71.6 amps.
But you'll have to figure how that fits into the code (e.g. if you need to do the 125% circuit rating in that situation). I'm not a licensed EC; I just do computer room designs and outsource the electrical work to ECs after I've done all my calculations.
[This message has been edited by pdh (edited 01212005).]



Re: Load Calc for 18kV W/H
#91534
01/21/05 06:24 PM

Joined: Jan 2005
Posts: 354
Member

OK, based on what mike d says, and you need to put it on a 125% circuit, given the 57.28 amps on 2 of the 3 phases, and 125% being 71.6 amps, you'll probably have to put it on an 80 amp circuit.



Re: Load Calc for 18kV W/H
#91535
01/21/05 10:18 PM

Joined: Mar 2001
Posts: 333
Member

You state the service is 3 phase, but are you sure the water heater is 3 phase? I find it hard to believe a 3 phase W/H would not have 3, 6 or 9 elements.
steve
Steve



Re: Load Calc for 18kV W/H
#91536
01/22/05 01:39 AM

Joined: Jan 2005
Posts: 354
Member

While doing a little shopping for water heaters a couple months ago, to get some specifications an options for planning a house build way in the future, I downloaded technical details on many water heaters from several manufacturers, including commercial models because they had more of the pointofuse types I was interested in. In these technical details were wiring instructions and diagrams. I looked at the 3 phase models, too, because I was curious. Some can even be rewired between 1 phase and 3 phase.
The larger commercial models did have a multiple of 3 for the number of elements. But some smaller models did have 2 or 4 elements. What caught my attention was that the replacement element model numbers for 1 phase and 3 phase versions of the same model line were the same. That's not easy to do unless the element really has 6 coils, and that would be an expensive way to manufacture them.
I did look at a 2 element model for 3 phase rather closely. It did indeed place one element on AB and the other element on BC. So the B phase would be drawing more current than A or C. My guess is this was done to minimize the overall costs and use the same line of elements between 1 phase and 3 phase, and make it possible to field rewire the phase configuration.
In smaller models, 2 elements, or maybe 4 elements, makes more sense due to having upper and lower heating elements. 6 elements would make sense, too, but the cost is getting high there, and that would not be viable for smaller models. If you need 9000 watts, 2 elements of 4500 watts is much less costly than 6 elements of 1500 watts.
Equally balanced, 18000 watts would be 50 amps on 208/120. But the stated 57 amps didn't come close to the 125% figure of 62.5 amps you get from the well balanced case. So I assumed that wasn't indicating the necessary circuit size. So I ran the numbers for the current based on balancing 4 elements the best that can be done on 3 phase, and it came up with 57.282196187 amps. Close enough to 57. Thus I have to conclude that this is a water heater with 4 elements wired as such, because I can see no other reason for listing 57 amps on the nameplate.
Anyway, I do know for a fact that water heaters are made this way with that number of elements. With the load numbers matching, what else can it be?




