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Joined: Mar 2005
Posts: 88
J
JFLS41 Offline OP
Member
Help me to properly understand the 220.19 table for computing the demand factor for a 11KVa stove. Do you multiply 11,000 x 8 = 880 or do you figure it 8 x 1000 = 8,000? Not sure if I'm doing it right.

Thanks

Joined: Feb 2002
Posts: 182
B
Bob Offline
Member
Read note 2 under the table. It explains the prodeedure.

Joined: Mar 2005
Posts: 88
J
JFLS41 Offline OP
Member
I read that, still scratching my head... care to explain if you don't mind?

thanks

Joined: May 2002
Posts: 1,716
R
Member
When using column C the math is already done. (1) 11kw range = 8kw, or 8 x 1000 as you said.

Roger

[This message has been edited by Roger (edited 04-26-2005).]


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