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Joined: Jul 2007
Posts: 1,335
S
Member
Just carious. If I had running data from with the primary or secondary side of a transformer, can the other side be calculated based off of the transformer data plate or perhaps other data?


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Joined: Sep 2011
Posts: 21
A
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Volt-amps in = volt-amps out + losses.

Joined: Jul 2004
Posts: 9,942
Likes: 34
G
Member
It is calculating those "losses" that separate electricians from engineers. wink


Greg Fretwell
Joined: Mar 2004
Posts: 947
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twh Offline
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My guess is the losses are I squared x R, calculated for the line side and the load side. I don't think the hum uses much power.

Joined: Nov 2002
Posts: 794
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W
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There's also the losses in the transformer laminations. Better quality steel would have lower losses, but would be more expensive. The transformer would not get as hot while it is powered but unloaded. Probably less hum.

Joined: Jul 2004
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G
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If Scott stops by I am sure he can tell us about a whole lot of things that affect "loss" in a transformer. I have bumped around the edges of this stuff but just enough to understand this is more than 2 coils of wire and a core when you get down to the nitty gritty of the difference between the "goesinna" and the "comesoutta". The only thing I know is the loss ends up being mostly heat so the temp this thing runs at is a pretty good clue about the efficiency.


Greg Fretwell

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