Am I missing something? Why is everyone trying to change this calculation to volt-amps when Frank has stated that each fixture draws 8.2 amps?
Doing the Volt-Amp thing might be advantageuos if this load could be equally shared by all three phases, but since it can't, I feel the resulting answers are too low. The math is correct, so I'll assume that everyone slipped off their boots to use their toes
![[Linked Image]](https://www.electrical-contractor.net/ubb/biggrin.gif)
and they all did their gazintas correctly.
There will be 15 fixtures on A phase x 8.2 = 123 amps, 15 fixtures on B phase x 8.2 amps = 123 amps
C phase only has 14 fixtures x 8.2 amp=114.8 amp.
125 amps x 125% = 153.75 amps, too much for 150 amp feeder or 150 amp panel.