Am I missing something? Why is everyone trying to change this calculation to volt-amps when Frank has stated that each fixture draws 8.2 amps?
Doing the Volt-Amp thing might be advantageuos if this load could be equally shared by all three phases, but since it can't, I feel the resulting answers are too low. The math is correct, so I'll assume that everyone slipped off their boots to use their toes
and they all did their gazintas correctly.
There will be 15 fixtures on A phase x 8.2 = 123 amps, 15 fixtures on B phase x 8.2 amps = 123 amps
C phase only has 14 fixtures x 8.2 amp=114.8 amp.
125 amps x 125% = 153.75 amps, too much for 150 amp feeder or 150 amp panel.