




#68027  07/28/06 12:55 PM
Re: Calculating neutral loads.

Member
Registered: 12/12/04
Posts: 1091
Loc: nowhere usa

Trick, the A,B,C are the currents in phase A, Phase B, and Phase C.
So for a split(single)phase service, the nuetral current is the unbalnced current flowing between phase A and phase B.
So if 30 amps were flowing on phase A, and 15 amps were flowing on Phase B, the nuetral current would be: Yes it is a minus...
AB=N 3015=15
On a wye service, if we had 150amps on A, 110amps on B, and 75amps on C.
N= Sq root of (A^+B^+C^)(AB+AC+CB) N=Sq root of (150^+110^+75^)((150*110)+(150*75)+(75*110) N=Sq root of (22500+12100+5625)((16500)+(11250)+(8250)) N=Sq root of (40225)(36000) N=Sq root of (4225) N=65 amps
How does that look?
[This message has been edited by Dnkldorf (edited 07282006).]

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#68030  07/30/06 02:44 PM
Re: Calculating neutral loads.

Member
Registered: 12/12/04
Posts: 1091
Loc: nowhere usa


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