this thing is what i am thinking about for longer time, there's a big discussion in another german elecrics forum, VDE has different meanings on this that dont give me clearness at all.
Using a 5x1,5mm² cable with L1 L2 L3 N PE, split for three 230V->N radials.
Now what if the load is asymmetric.
then the shared neutral, in case of 2 loads of 16A and one load of 0A will run 16A if i'm right.
Now what if there are phase shifts from inductive loads. Will the current on the neutral then raise above 16A (i think so), and how to calculate it?
lets say i have 16A inductive load with a phase shift of 90° and a 16A resistive load. is the current on neutral then nearly 32A?
tested with this animation: http://www.walter-fendt.de/ph11d/reskraft.htm
select "3" in the pulldown menu, then klick "gesamtkraft ermitteln".
just form the pointers to a triangle until the red one is in the middle. then move one phase to the middle, red pointer will show 16A between the two left over phases. now turn one left phase 90deg in direction of the other one. the red one's lenght will nearly double.
is this animation useable in this way for the current calculation?
[This message has been edited by :andy: (edited 12-05-2003).]