Here is a simple example of the Power Triangle, which will assist with the Power Factor conclusion:

(it also doubles as the Basic Impedance Triangle, and the Basic Pythagoris Theorym)

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4 Watts (True Power),

3 VARs (Reactive Power),

5 VAs (Apparent Power).

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Power Factor = 0.8 (80%) lagging

4 Watts is 80% of 5 VA.

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Some detail to these items:

*** WATTS ***

Watts = True Power,

KW = Kilo Watts = 1,000 Watts;

*** VA ***

VA = Volt-Amps = Apparent Power = Reactive Power and True Power compiled,

KVA = Kilo Volt-Amps = 1,000 Volt-Amps = 1,000 VA;

*** VAR ***

VAR = Volt-Amps Reactive = Reactive Power = Scuttle Power,

KVAR = Kilo Volt-Amps Reactive = 1,000 Volt-Amps Reactive = 1,000 VAR.

In the example values listed above, the preceeding relate to listed Trigonomic Terms:

[*] 4 Watts = "Sine" (Base of the Triangle),

[*] 3 VARs = "Cosine" (Opposite side of Triangle),

[*] 5 VAs = "Tangent" (Hypotenuse)

You can use this formula to find any single unknown value, as long as you have two known values.

Scott35