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Posted By: cinkerf Voltage drop calculation - 01/04/02 01:44 PM
In today's code question of day http://www.ecmag.com/cqd/index.cfm?ID=20020104 two methods for performing voltage drop calculations were given for an A.C. circuit. Is one method better than other? Is one method more popular than the other?
Posted By: Bill Addiss Re: Voltage drop calculation - 01/04/02 01:57 PM
Frank,

I've always tried to use formulas that are simple (for me) to remember. In this case Ohm's Law; (I = E/R)

E = I x R where E is the Voltage

Bill
Posted By: Frank Cinker Re: Voltage drop calculation - 01/04/02 03:18 PM
Thanks Bill. By the way, Happy New Year....
Posted By: JBD Re: Voltage drop calculation - 01/04/02 03:21 PM
For short distances (less than 150 ft), I use simple formulas. I like the Square D Motor Data Calculator voltage drop feature.

For longer distances I like to consider the impedance of the system rather than only the resistance. This means worrying about the raceway, Power Factor, and phase configuration. I use the tables in the Ferraz-Shawmut Book of Electrical Information.
Posted By: resqcapt19 Re: Voltage drop calculation - 01/04/02 06:09 PM
I just found this site with some downloadable elecrical software. It has a series voltage drop calculator for multiple loads on long runs. It is free and I downloaded it this morning. Looks like it will work nice, but I haven't really played with it yet. http://www.edreference.com/default.asp
Don(resqcapt19)
Posted By: Frank Cinker Re: Voltage drop calculation - 01/04/02 10:16 PM
Over the years I've take several certification examinations. Only small calculators were permitted to be used. I've had luck using the following calculation for voltage drop for single phase circuits: VD=2KLI/CM. x.866 if three phase circuit. For these particular exam questions power factor, raceway etc were not a factor. I was thankful for that...

For those of you who took exams, what formula did you use?

[This message has been edited by Frank Cinker (edited 01-06-2002).]
Posted By: George Corron Re: Voltage drop calculation - 01/09/02 11:49 AM
Guys,
Ugly's has always been the standard around here. Don, Uglys was issued to me by the IBEW in my apprenticeship, since we came through about the same time didn't you use it ? If they quit publishing Uglys I've always said I'm leaving the trade. It is also the standard used locally for most every test.

Single phase, 2 wire = 2K X L X I / Cm

3 phase, 3 wire = 1.73K X L X I/ Cm

K = 12.9 for copper, 21.2 for aluminum
L = length, I = amps, and Cm = Circular mil area from Chap 9, Table 8

The only thing you have to check occasionally is the "K" rating, that has moved around since I came in the trade because the cma table was revised.

I've been around long enough that #10 wire was 10,000 cm, it has been revised to 10,380, but the formula has pretty much remained the same. [Linked Image]
Posted By: resqcapt19 Re: Voltage drop calculation - 01/11/02 03:33 AM
George,
They didn't give us "Ulglys", but those are the formulas that we were taught.
Don
Posted By: Elzappr Re: Voltage drop calculation - 01/11/02 07:41 AM
The K factor has changed through the years because the Ohms per 1000ft figure in Table 8 of Ch 9 depends on the assumed temperature. In the '87 code they stopped assuming 25C and started assuming 75C.
K is just shorthand for: (dc resistance value) X (circular mil area) divided by 1000.
You have to watch out for the assumed temperature if you are going to use the formula with a K factor...not to be confused with K factors of transformers!

[This message has been edited by Elzappr (edited 01-11-2002).]
Posted By: sparky66wv Re: Voltage drop calculation - 01/12/02 04:48 AM
I would not have passed my journeyman's without an UGLY's... Is the 2002 out yet?
Posted By: WARREN1 Re: Voltage drop calculation - 01/24/02 02:54 PM
Another handy reference for your computer, for those who do not have it, is:
edreference.com
(I hope this works).
It has voltage drop, short circuit calculations and some other stuff included.
Posted By: bob3232 Re: Voltage drop calculation - 02/11/02 10:33 AM
I like this one.

2xLxIxohms per k from table 8, divide by 1000
L= length
I= amps
2= distance both ways
For 3 phase .866xvd
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