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#97631 03/14/06 12:55 PM
Joined: Jun 2005
Posts: 821
S
Member
That is an excellent explanation.

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#97632 03/14/06 09:22 PM
Joined: Feb 2002
Posts: 183
N
Member
Not quite. Using ohm's law, at 110V, the 10A load has 11 ohms resistance. The 1A load has 110 ohms resistance. Assuming the resistance doesn't change (not true with light bulbs since the resistance depends on temperature and therefore power...), if the neutral opens,
we now have 110 ohms in series with 11 ohms
(121 ohms) across 220V. In that case the current in either is 1.82A. The 10A load will see 18.2 volts across it and the 1A load will see 182V across it, until it blows.

/mike

#97633 03/15/06 10:56 PM
Joined: Jan 2004
Posts: 1,507
G
Member
n1ist-You are correct with your math approach but the end result would be the same. You'd burn out something- what ever was the weakest point.


George Little
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