The electrical plan reviewer at the AHJ wanted the loads balanced on all phases (A,B,C) for the water heater on the panel schedule.
As follows:
57A * 208V * 1.732 = 20534.592 / 3 = 6844.864
PH-A: 6845VA
PH-B: 6845VA
PH-C: 6845VA
This got me thinking about the following quote regarding PH-C VA for the water heater by pdh.
Quote: pdh - (posted 01-25-2005 08:02 AM)
"It's going to have 4500 VA and watts, and unity power factor (assuming resistive elements). It's current will be 37.5 amps."
Regarding the above quote...
Is the unity power factor for the PH-C load a result of having a balanced load for 3 of the elements in water heater?
Therfore is it correct to say that the 4500w can be divided by a PF of 1.0 (because of unity power factor) for a result of a 4500VA load on PH-C?
Thanks,
Mario
