Hell-o, New guy here,
just to jump in on the capacitor problem
2 capacitors in series of 1MFD and 2MFD
Scott is correct.
Ct= .666 MFD
Qt = Q1 = Q2
then Qt = Ct x E (assume E=12 VDC)
.667E-6 x 12 = 8E-6

V1 = Qt/C1 = 8E-6/1E-6 = 8 volts
V2 = Qt/C2 = 8E-6/2E-6 = 4 volts

E = V1 + V2 thus 8 + 4 = 12
and thats the way I see it.
Tom


Thomas-F