I'm doing the Mike Holt series of workbooks for basic electrical theory (I also have a test tonight at school), and I'd just like to check my work to make sure I'm "gettin' it" if you know what I mean.

Question #32:

What is the voltage drop of two 12 AWG conductors, each 100 feet in length, supplying a 2-wire, 16A Load? The resistance of 12 AWG conductors is 2? per 1,000 feet.

So, Evd = I X R

I = 16

R = 2? per 1000'/ 1000 = 0.002

.002 x 200' (round trip) = 0.4

E = I (16) X R (0.4)

Evd = 6.4v

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Correct?